The parallel combination of two air filled parallel plate capacitors… | JEE Main 2019 (9 Apr, Shift 2)

Q99JEE Main 2019 · 9 APR · SHIFT 2Difficult

Dielectrics

The parallel combination of two air filled parallel plate capacitors of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitor. The new potential difference of the combined system is :-

Show answer and solution

Answer: (c)

Charge: $Q = (C + nC)V = (n+1)CV$ , constant after the battery is removed.
New capacitance: $KC + nC = (K + n)C$ .
$V' = \frac{(n+1)V}{K+n}$ , so the answer is (c).

Report a mistake

More questions on Dielectrics

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If…JEE Main 2018
A combination of parallel plate capacitors is maintained at a certain potential…JEE Main 2017 (9 Apr, Shift 1)
A parallel-plate capacitor of area A, plate separation d and capacitance C is filled with…NEET 2016 (Phase 2)
A parallel plate air capacitor of capacitance C is connected to a cell of emf V and then…NEET 2015 (AIPMT, Cancelled Paper)
A parallel plate capacitor is made of two circular plates separated by a distance 5 mm…JEE Main 2014
Two thin dielectric slabs of dielectric constants K1 and K2(K1 < K2) are inserted between…NEET 2014 (AIPMT)
The gap between the plates of a parallel plate capacitor of area A and distance between…JEE Main 2014 (19 Apr, Shift 1)
The space between the plates of a parallel plate capacitor is filled with a 'dielectric'…JEE Main 2014 (12 Apr, Shift 1)

Dielectrics question from JEE Main 2019 (9 Apr, Shift 2)

More questions on Dielectrics