The percentage error in the measurement of g is: (Given that g = (4π² L)/(T²), L = (10 ± 0.1) cm, T = (100 ± 1) s) (a) 7% (b) 2% (c) 5% (d) 3%

Answer: (d). g = (4π² L)/(T²), so (Δ g)/(g) = (Δ L)/(L) + 2(Δ T)/(T) = 0.1/10 + 2·1/100 = 1% + 2% = 3% So the answer is (d) 3%.

The percentage error in the measurement of g is: (Given that g = (4π²… | NEET 2022 (Phase 2)

Q72NEET 2022 · PHASE 2Easy

Errors in Measurement

The percentage error in the measurement of g is: (Given that $g = \frac{4\pi^2 L}{T^2},\ L = (10 \pm 0.1)$ cm, $T = (100 \pm 1)$ s)

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Answer: (d)

$g = \frac{4\pi^2 L}{T^2}$ , so $\frac{\Delta g}{g} = \frac{\Delta L}{L} + 2\frac{\Delta T}{T}$
$= \frac{0.1}{10} + 2\cdot\frac{1}{100} = 1\% + 2\% = 3\%$
So the answer is (d) 3%.

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