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JEE Main 2018 (16 Apr, Shift 1) · Errors in Measurement

Errors in Measurement question from JEE Main 2018 (16 Apr, Shift 1)

Q98JEE Main 2018 · 16 APR · SHIFT 1Medium

Errors in Measurement

The percentage errors in quantities P, Q, R and S are 0.5%, 1%, 3% and 1.5% respectively in the measurement of a physical quantity A = P3Q2RS\frac{P^{3} Q^{2}}{\sqrt{RS}}

The maximum percentage error in the value of A will be:

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Answer: (d)

  1. Official JEE form: A=P3Q2R SA = \frac{P^3 Q^2}{\sqrt{R}\, S}, so ΔAA=3ΔPP+2ΔQQ+12ΔRR+ΔSS\frac{\Delta A}{A} = 3\frac{\Delta P}{P} + 2\frac{\Delta Q}{Q} + \frac{1}{2}\frac{\Delta R}{R} + \frac{\Delta S}{S}
  2. =3(0.5)+2(1)+12(3)+1.5=1.5+2+1.5+1.5=6.5%= 3(0.5) + 2(1) + \frac{1}{2}(3) + 1.5 = 1.5 + 2 + 1.5 + 1.5 = 6.5\%
  3. So the answer is (d) 6.5%6.5\%.
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