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NEET 1997 (AIPMT) · Kepler's Laws & Planetary Motion

Kepler's Laws & Planetary Motion question from NEET 1997 (AIPMT)

Q29NEET 1997 · AIPMTEasy

Kepler's Laws & Planetary Motion

The period of revolution of planet $A$ around the sun is 8 times that of $B$ . The distance of $A$ from the sun is how many times greater than that of $B$ from the sun?

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Answer: (a)

Kepler's third law: $r \propto T^{2/3}$ .
$\dfrac{r_A}{r_B} = 8^{2/3} = 4$
So the answer is (a) 4.

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