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MHT CET 2025 (20 Apr, Shift 1) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2025 (20 Apr, Shift 1)

Q17MHT CET 2025 · 20 APR · SHIFT 1Easy

Periodic Motion & SHM Basics

The period of S. H.M. of a particle is 16 second. The phase difference between the positions at t=2 st = 2\text{ s} and t=4 st = 4\text{ s} will be

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Answer: (c)

  1. Phase difference Δϕ=2πTΔt\Delta\phi = \frac{2\pi}{T}\Delta t.
  2. Δϕ=2π16×(4−2)=π4\Delta\phi = \frac{2\pi}{16}\times(4 - 2) = \frac{\pi}{4}.
  3. So the answer is (c) π4\frac{\pi}{4}.
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