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MHT CET 2026 (15 May, Shift 1) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2026 (15 May, Shift 1)

Q2MHT CET 2026 · 15 MAY · SHIFT 1Easy

Periodic Motion & SHM Basics

The period of S.H.M. of a particle is $12$ s. The phase difference between the positions at $t = 3$ s and $t = 4$ s will be

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Answer: (c)

Phase difference $\Delta\phi = \frac{2\pi}{T}\Delta t$ .
$\Delta\phi = \frac{2\pi}{12}\times(4 - 3) = \frac{\pi}{6}$ .
So the answer is (c) $\frac{\pi}{6}$ .

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