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MHT CET 2026 (20 Apr, Shift 1) · Vibration Magnetometer

Vibration Magnetometer question from MHT CET 2026 (20 Apr, Shift 1)

Q1MHT CET 2026 · 20 APR · SHIFT 1Easy

Vibration Magnetometer

The periodic time of a magnet in vibration magnetometer is T0T_0. If a magnet is replaced by another magnet whose moment of inertia is three times and magnetic moment is one-third of the original magnet, then time period of new magnet will be

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Answer: (c)

  1. T=2πIMB⇒T∝IMT = 2\pi\sqrt{\frac{I}{MB}} \Rightarrow T \propto \sqrt{\frac{I}{M}}
  2. TT0=3II⋅MM/3=9=3\frac{T}{T_0} = \sqrt{\frac{3I}{I} \cdot \frac{M}{M/3}} = \sqrt{9} = 3
  3. So the answer is (c) 3T03T_0.
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