Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Velocity & Acceleration in SHM›Question 79

NEET 2007 (AIPMT) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from NEET 2007 (AIPMT)

Q79NEET 2007 · AIPMTEasy

Velocity & Acceleration in SHM

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

Show answer and solution

Answer: (d)

  1. x=Asin⁡ωtx = A\sin\omega t, v=Aωcos⁡ωt=Aωsin⁡(ωt+π2)v = A\omega\cos\omega t = A\omega\sin(\omega t + \frac{\pi}{2}).
  2. a=−Aω2sin⁡ωt=Aω2sin⁡(ωt+π)a = -A\omega^2\sin\omega t = A\omega^2\sin(\omega t + \pi).
  3. Phase difference between vv and aa =π−π2=π2=0.5π= \pi - \frac{\pi}{2} = \frac{\pi}{2} = 0.5\pi.
  4. So the answer is (d) 0.5π0.5\pi.
Report a mistake

More questions on Velocity & Acceleration in SHM