Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Doppler Effect›Question 25

MHT CET 2024 (3 May, Shift 1) · Doppler Effect

Doppler Effect question from MHT CET 2024 (3 May, Shift 1)

Q25MHT CET 2024 · 3 MAY · SHIFT 1Medium

Doppler Effect

The pitch of a whistle of an engine appears to drop by 30%30\% of original value when it passes a stationary observer. If the speed of sound in air is 350 ms−1350\text{ ms}^{-1}, then the speed of engine in ms−1\text{ms}^{-1} is

Show answer and solution

Answer: (d)

  1. After passing, the engine recedes and the heard pitch is 70% of the original: f′=f vv+u=0.7ff' = f\,\dfrac{v}{v + u} = 0.7f.
  2. 350=0.7(350+u)⇒350+u=500350 = 0.7(350 + u) \Rightarrow 350 + u = 500
  3. So the answer is (d) u=150 m/su = 150\text{ m/s}.
Report a mistake

More questions on Doppler Effect