The pitch of an error free screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads 1 mm and 63 rd division on the circular scale coincides with the reference line. The diameter of the wire is: (a) 1.63 cm (b) 0.163 cm (c) 0.163 m (d) 1.63 m

Answer: (b). LC = (1 mm)/(100) = 0.01 mm Diameter = 1 + 63× 0.01 = 1.63 mm = 0.163 cm, answer (b).

The pitch of an error free screw gauge is 1 mm and there are 100… | NEET 2024

Q23NEET 2024Medium

Least Count, Vernier Callipers & Screw Gauge

The pitch of an error free screw gauge is $1\text{ mm}$ and there are 100 divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads $1\text{ mm}$ and $63$ rd division on the circular scale coincides with the reference line. The diameter of the wire is:

Show answer and solution

Answer: (b)

LC $= \dfrac{1\text{ mm}}{100} = 0.01$ mm
Diameter $= 1 + 63\times 0.01 = 1.63$ mm
$= 0.163$ cm, answer (b).

Report a mistake

Least Count, Vernier Callipers & Screw Gauge question from NEET 2024

More questions on Least Count, Vernier Callipers & Screw Gauge