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MHT CET 2025 (26 Apr, Shift 2) · Electric Field & Field Lines

Electric Field & Field Lines question from MHT CET 2025 (26 Apr, Shift 2)

Q8MHT CET 2025 · 26 APR · SHIFT 2Medium

Electric Field & Field Lines

The point charges +q,−q,−q,+q,+Q+q, -q, -q, +q, +Q and -q are placed at the vertices of a regular hexagon ABCDEF as shown in figure. The electric field at the centre of hexagon ' OO ' due to the five charges at A,B,C,DA, B, C, D and F is twice the electric field at centre ' O ' due to charge +Q at E alone. The value of QQ is

Figure

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Answer: (a)

  1. Opposite pairs A,DA, D (+q,+q+q, +q) and C,FC, F (−q,−q-q, -q) give zero field at OO.
  2. Field of the five charges = field of −q-q at BB: kqr2\dfrac{kq}{r^2} towards BB.
  3. Field of +Q+Q at EE: kQr2\dfrac{kQ}{r^2}, also towards BB.
  4. kqr2=2kQr2⇒Q=q2\dfrac{kq}{r^2} = 2\dfrac{kQ}{r^2} \Rightarrow Q = \dfrac{q}{2}
  5. So the answer is (a) q2\dfrac{q}{2}.
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