The polarising angle of transparent medium is ' θ '. Let the speed of light in the medium be ' v '. Then the relation between ' θ ' and ' v ' is [ c = velocity of light in air] (a) θ = sin ⁻¹(v/c) (b) θ = tan ⁻¹(v/c) (c) θ = cot ⁻¹(v/c) (d) θ = cos ⁻¹(v/c)

Answer: (c). Brewster's law: tan θ = μ = c/v cot θ = v/c ⇒ θ = cot ⁻¹(v/c) So the answer is (c).

The polarising angle of transparent medium is ' θ '. Let the speed of… | MHT CET 2025 (26 Apr, Shift 2)

Q23MHT CET 2025 · 26 APR · SHIFT 2Medium

Polarisation

The polarising angle of transparent medium is ' $\theta$ '. Let the speed of light in the medium be ' v '. Then the relation between ' $\theta$ ' and ' $\mathrm{v}$ ' is [ $\mathrm{c} =$ velocity of light in air]

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Answer: (c)

Brewster's law: $\tan\theta = \mu = \frac{c}{v}$
$\cot\theta = \frac{v}{c} \Rightarrow \theta = \cot^{-1}\left(\frac{v}{c}\right)$
So the answer is (c).

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Polarisation question from MHT CET 2025 (26 Apr, Shift 2)

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