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JEE Main 2021 (22 Jul, Shift 2) · Continuous Bodies: Standard Results & Variable Density

Continuous Bodies: Standard Results & Variable Density question from JEE Main 2021 (22 Jul, Shift 2)

Q3JEE Main 2021 · 22 JUL · SHIFT 2Easy

Continuous Bodies: Standard Results & Variable Density

The position of the centre of mass of a uniform semi-circular wire of radius 'R' placed in x-y plane with its centre at the origin and the line joining its ends as x-axis is given by (0,xRπ)\left(0, \frac{xR}{\pi}\right). Then, the value of | x | is ______________.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. For a uniform semicircular wire, ycm=2Rπy_{cm} = \frac{2R}{\pi} from the centre.
  2. Comparing with xRπ\frac{xR}{\pi}: ∣x∣=2|x| = 2
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