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NEET 2015 (AIPMT) · Motion in a Plane (2-D Kinematics)

Motion in a Plane (2-D Kinematics) question from NEET 2015 (AIPMT)

Q16NEET 2015 · AIPMTMedium

Motion in a Plane (2-D Kinematics)

The position vector of a particle R⃗\vec{R}as a function of time is given by R⃗\vec{R} = 4sin(2πt)i^\pi t)\hat{i} + 4cos(2πt)j^\pi t)\hat{j}. Where R is in meters, t is in seconds and i^\hat{i} and j^\hat{j} denote unit vectors along x-and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?

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Answer: (a)

  1. ∣R⃗∣=4|\vec R| = 4 m always, so the path is a circle of radius 4 m: (b) true.
  2. v⃗=8πcos⁡(2πt)i^−8πsin⁡(2πt)j^\vec v = 8\pi\cos(2\pi t)\hat i - 8\pi\sin(2\pi t)\hat j, so ∣v⃗∣=8π|\vec v| = 8\pi m/s, not 8 m/s: (a) wrong.
  3. a⃗=−4π2R⃗\vec a = -4\pi^2\vec R, along −R⃗-\vec R with magnitude v2R\frac{v^2}{R}: (c), (d) true.
  4. So the wrong statement is (a).
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