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NEET 1997 (AIPMT) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from NEET 1997 (AIPMT)

Q48NEET 1997 · AIPMTEasy

Velocity, Acceleration & Variable Motion

The position $x$ of a particle varies with time ( $t$ ) as $x = at^2 - bt^3$ . The acceleration will be zero at time $t$ is equal to

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Answer: (a)

$v = 2at - 3bt^2$ , acceleration $= 2a - 6bt$ .
$2a - 6bt = 0 \Rightarrow t = \frac{a}{3b}$
So the answer is (a) $\frac{a}{3b}$ .

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