Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Photoelectric Effect: Einstein's Equation›Question 157

NEET 2010 (AIPMT, Prelims) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from NEET 2010 (AIPMT, Prelims)

Q157NEET 2010 · AIPMT · PRELIMSEasy

Photoelectric Effect: Einstein's Equation

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work functions 5.01 eV, when ultraviolet light of 200 nm falls on it, must be

Show answer and solution

Answer: (b)

  1. E=1240200=6.2 eVE = \frac{1240}{200} = 6.2\text{ eV}
  2. Kmax=6.2−5.01=1.19≈1.2 eVK_{max} = 6.2 - 5.01 = 1.19 \approx 1.2\text{ eV}, so ∣V0∣=1.2 V|V_0| = 1.2\text{ V}.
  3. The collector must be negative with respect to the plate to repel the electrons.
  4. So the answer is (b) −1.2-1.2 V.
Report a mistake

More questions on Photoelectric Effect: Einstein's Equation