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NEET 2016 (Phase 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from NEET 2016 (Phase 2)

Q176NEET 2016 · PHASE 2Medium

Kirchhoff's Laws & Measuring Instruments

The potential difference (VA $-$ VB) between the points A and B in the given figure is

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Answer: (d)

Walk from A to B along $I = 2\text{ A}$ : drop $IR$ in each resistor, drop $E$ across the cell (+ to −).
$V_A - 2(2) - 3 - 2(1) = V_B$
$V_A - V_B = 4 + 3 + 2 = 9\text{ V}$
So the answer is (d) +9 V.

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