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NEET 2006 (AIPMT) · Spring & Elastic Energy

Spring & Elastic Energy question from NEET 2006 (AIPMT)

Q29NEET 2006 · AIPMTEasy

Spring & Elastic Energy

The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is

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Answer: (d)

$U = \frac{1}{2}kx^2 \Rightarrow U \propto x^2$ .
$\frac{U'}{U} = \left(\frac{8}{2}\right)^2 = 16$
So the answer is (d) $16U$ .

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