The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm, potential energy stored in it will be: (a) 4U (b) 8U (c) 16U (d) 2U

Answer: (c). U = 1/2kx², so U ∝ x². U'/U = (8/2)² = 16 So the answer is (c) 16U.

The potential energy of a long spring when stretched by 2 cm is U. If… | NEET 2023

Q7NEET 2023Easy

Spring & Elastic Energy

The potential energy of a long spring when stretched by $2\text{ cm}$ is U. If the spring is stretched by $8\text{ cm}$ , potential energy stored in it will be:

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Answer: (c)

$U = \frac{1}{2}kx^2$ , so $U \propto x^2$ .
$\frac{U'}{U} = \left(\frac{8}{2}\right)^2 = 16$
So the answer is (c) $16U$ .

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