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NEET 2024 · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from NEET 2024

Q16NEET 2024Easy

Applications of Dimensional Analysis

The potential energy of a particle moving along xx-direction varies as V=Ax2x+BV = \frac{Ax^2}{\sqrt{x} + B}. The dimensions of A2B\frac{A^2}{B} are:

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Answer: (c)

  1. Only like quantities can be added: [B]=[x]=[L1/2][B] = [\sqrt{x}] = [L^{1/2}].
  2. [V]=[A][L2]/[L1/2]⇒[A]=[ML2T−2][L−3/2]=[ML1/2T−2][V] = [A][L^2]/[L^{1/2}] \Rightarrow [A] = [ML^2T^{-2}][L^{-3/2}] = [ML^{1/2}T^{-2}].
  3. [A2/B]=[M2LT−4]/[L1/2]=[M2L1/2T−4][A^2/B] = [M^2LT^{-4}]/[L^{1/2}] = [M^2L^{1/2}T^{-4}].
  4. So the answer is (c).
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