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NEET 2003 (AIPMT) · Energy in SHM

Energy in SHM question from NEET 2003 (AIPMT)

Q76NEET 2003 · AIPMTEasy

Energy in SHM

The potential energy of a simple harmonic oscillator when the particle is half way to its end point is

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Answer: (c)

  1. Halfway to the end point: x=A/2x = A/2.
  2. PE=12kA24=14⋅12kA2=E4PE = \dfrac{1}{2}k\dfrac{A^2}{4} = \dfrac{1}{4}\cdot\dfrac{1}{2}kA^2 = \dfrac{E}{4}
  3. So the answer is (c) 14E\dfrac{1}{4}E.
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