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MHT CET 2023 (9 May, Shift 1) · Dielectrics

Dielectrics question from MHT CET 2023 (9 May, Shift 1)

Q52MHT CET 2023 · 9 MAY · SHIFT 1Easy

Dielectrics

The potential energy of charged parallel plate capacitor is $v_0$ . If a slab of dielectric constant $K$ is inserted between the plates, then the new potential energy will be

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Answer: (a)

A charged capacitor (no battery) keeps its charge $Q$ .
$U = \frac{Q^2}{2C}$ and $C' = KC$ , so $U' = \frac{U}{K}$ .
So the answer is (a) $\frac{v_0}{K}$ .

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