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MHT CET 2026 (19 May, Shift 1) · Potentiometer

Potentiometer question from MHT CET 2026 (19 May, Shift 1)

Q1MHT CET 2026 · 19 MAY · SHIFT 1Easy

Potentiometer

The potential gradient along the length of 1 metre wire of uniform cross section is $6$ V/m. Let ' $B$ ' and ' $C$ ' be the two points at $40$ cm and $60$ cm marks respectively from one end. The potential difference between points B and C is

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Answer: (a)

$V_{BC} = k \times BC$ with $BC = 60 - 40 = 20\text{ cm} = 0.2\text{ m}$ .
$V_{BC} = 6 \times 0.2 = 1.2\text{ V}$ .
So the answer is (a) 1.2 V.

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