The potential on the plates of capacitor are +20 V and -20 V. The charge on the plate is 40 C. The capacitance of the capacitor is (a) 2 F (b) 1 F (c) 4 F (d) 0.5 F

Answer: (b). Potential difference V = 20 - (-20) = 40 V. C = Q/V = 40/40 So the answer is (b) 1 F.

The potential on the plates of capacitor are +20 V and -20 V. The… | MHT CET 2023 (12 May, Shift 1)

Q8MHT CET 2023 · 12 MAY · SHIFT 1Easy

Capacitance of a Conductor

The potential on the plates of capacitor are $+20\text{ V}$ and $-20\text{ V}$ . The charge on the plate is $40\text{ C}$ . The capacitance of the capacitor is

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Answer: (b)

Potential difference $V = 20 - (-20) = 40\text{ V}$ .
$C = \frac{Q}{V} = \frac{40}{40}$
So the answer is (b) $1\text{ F}$ .

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