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NEET 2012 (AIPMT, Mains) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from NEET 2012 (AIPMT, Mains)

Q56NEET 2012 · AIPMT · MAINSMedium

Electrical Power & Heating Effect

The power dissipated in the circuit shown in the figure is 30 watts. The value of R is

Figure

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Answer: (c)

  1. RR and 5 Ω5\ \Omega are in parallel across 10 V.
  2. P=V2R+V25=100R+20=30P = \dfrac{V^2}{R} + \dfrac{V^2}{5} = \dfrac{100}{R} + 20 = 30.
  3. 100R=10⇒R=10 Ω\dfrac{100}{R} = 10 \Rightarrow R = 10\ \Omega.
  4. So the answer is (c) 10 Ω10\ \Omega.
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