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NEET 2011 (AIPMT, Prelims) · Nuclear Fission & Fusion

Nuclear Fission & Fusion question from NEET 2011 (AIPMT, Prelims)

Q28NEET 2011 · AIPMT · PRELIMSMedium

Nuclear Fission & Fusion

The power obtained in a reactor using U235 disintegration is 1000 kW. The mass decay of U235 per hour is

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Answer: (c)

  1. Energy in one hour E=Pt=106×3600=3.6×109 JE = Pt = 10^6\times3600 = 3.6\times10^9\text{ J}.
  2. Mass converted m=Ec2=3.6×1099×1016=4×10−8 kgm = \dfrac{E}{c^2} = \dfrac{3.6\times10^9}{9\times10^{16}} = 4\times10^{-8}\text{ kg}.
  3. 4×10−8 kg=40 microgram4\times10^{-8}\text{ kg} = 40\text{ microgram}.
  4. So the answer is (c) 4040 microgram.
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