Student Login

Home›Chapters›Ray Optics PYQs›Spherical Surfaces & Thin Lenses›Question 82

NEET 2020 (Phase 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from NEET 2020 (Phase 2)

Q82NEET 2020 · PHASE 2Easy

Spherical Surfaces & Thin Lenses

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is,

Show answer and solution

Answer: (a)

$P = (\mu - 1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)$ with $R = 0.1$ m on both sides.
$10 = (\mu - 1)\left(\frac{2}{0.1}\right) = 20(\mu - 1)$
$\mu - 1 = 0.5 \Rightarrow \mu = 1.5$
So the answer is (a) $\frac{3}{2}$ .

Report a mistake

More questions on Spherical Surfaces & Thin Lenses

A plano-convex lens of unknown material and unknown focal length is given. With the help…NEET 2020 (Phase 2)
A point object in air is in front of the curved surface of a plano-convex lens. The…JEE Main 2020 (8 Jan, Shift 1)
A double convex lens has power P and same radii of curvature R of both the surfaces. The…JEE Main 2020 (6 Sep, Shift 2)
A thin lens made of glass (refractive index = 1.5) of focal length f = 16 cm is immersed…JEE Main 2020 (7 Jan, Shift 2)
For a concave lens of focal length f, the relation between object and image distances u…JEE Main 2020 (5 Sep, Shift 1)
The distance between an object and a screen is 100 cm. A lens can produce real image of…JEE Main 2020 (4 Sep, Shift 2)
The eye can be regarded as a single refracting surface. The radius of curvature of this…JEE Main 2019 (10 Jan, Shift 2)
A double convex lens has focal length 25 cm. The radius of curvature of one of the…NEET 2019