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MHT CET 2026 (15 Apr, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2026 (15 Apr, Shift 1)

Q2MHT CET 2026 · 15 APR · SHIFT 1Easy

Rotational Kinetic Energy, Work & Power

The power (P) is supplied to rotating body having moment of inertia 'I' and angular acceleration 'α\alpha'. Its instantaneous angular velocity is

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Answer: (d)

  1. Rotational power P=τωP = \tau\omega and τ=Iα\tau = I\alpha
  2. P=Iαω⇒ω=PIαP = I\alpha\omega \Rightarrow \omega = \frac{P}{I\alpha}
  3. So the answer is (d) PIα\frac{P}{I\alpha}.
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