Physics Circle home Student Login

Home›Chapters›Heat Transfer and Radiation PYQs›Thermal Radiation: Black Body, Stefan & Wien›Question 100

NEET 2018 · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from NEET 2018

Q100NEET 2018Medium

Thermal Radiation: Black Body, Stefan & Wien

The power radiated by a black body is P and it radiates maximum energy at wavelength, λ\lambda0. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 34λ0\frac{3}{4}\lambda_0, the power radiated by it becomes nP. The value of n is

Show answer and solution

Answer: (c)

  1. Wien's law: T∝1λmT \propto \frac{1}{\lambda_m}, so λm′=34λ0⇒T′=43T\lambda_m' = \frac{3}{4}\lambda_0 \Rightarrow T' = \frac{4}{3}T.
  2. Power P∝T4⇒nP=(43)4PP \propto T^4 \Rightarrow nP = \left(\frac{4}{3}\right)^4 P
  3. n=25681n = \frac{256}{81}
  4. So the answer is (c) 25681\frac{256}{81}.
Report a mistake

More questions on Thermal Radiation: Black Body, Stefan & Wien