The pressure acting on a submarine is 3 × 105 Pa at a certain depth… | JEE Main 2021 (16 Mar, Shift 1)

Q16JEE Main 2021 · 16 MAR · SHIFT 1Medium

Pressure in a Fluid

The pressure acting on a submarine is 3 $\times$ 105 Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be:

(Assume that atmospheric pressure is 1 $\times$ 105 Pa and density of water is 103 kg m ${}^{-3}$ , g = 10 ms ${}^{-2}$ )

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Answer: (b)

$P = P_0 + \rho g h$ : $3\times10^5 = 10^5 + 10^4 h \Rightarrow h = 20\text{ m}$ .
At $2h = 40\text{ m}$ : $P' = 10^5 + 10^4\times40 = 5\times10^5\text{ Pa}$ .
Increase $= \dfrac{5-3}{3}\times100 = \dfrac{200}{3}\%$
So the answer is (b).

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