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JEE Main 2024 (1 Feb, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2024 (1 Feb, Shift 1)

Q130JEE Main 2024 · 1 FEB · SHIFT 1Medium

Thermodynamic Processes

The pressure and volume of an ideal gas are related as PV32=KPV^{\frac{3}{2}} = K (Constant). The work done when the gas is taken from state A (P1,V1,T1)A\,(P_1, V_1, T_1) to state B (P2,V2,T2)B\,(P_2, V_2, T_2) is:

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Answer: (d)

  1. For PVx=KPV^{x} = K: W=P1V1−P2V2x−1W = \frac{P_1V_1 - P_2V_2}{x - 1}.
  2. Here x=32x = \frac{3}{2}, so x−1=12x - 1 = \frac{1}{2}.
  3. W=2(P1V1−P2V2)W = 2(P_1V_1 - P_2V_2)
  4. So the answer is (d).
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