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JEE Main 2022 (30 Jun, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2022 (30 Jun, Shift 1)

Q42JEE Main 2022 · 30 JUN · SHIFT 1Medium

Thermometry & Thermal Expansion

The pressure of the gas in a constant volume gas thermometer is 100 cm of mercury when placed in melting ice at 1 atm. When the bulb is placed in a liquid, the pressure becomes 180 cm of mercury. Temperature of the liquid is:

(Given 0 $^\circ$ C = 273 K)

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Answer: (d)

At constant volume, $\frac{P}{T}=$ constant: $\frac{T}{273}=\frac{180}{100}$
$T=273\times1.8=491.4$ K
So the answer is (d) 491 K.

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