The pressure ' P ', volume ' V ' and temperature ' T ' of a gas in a jar ' A ' and the gas in other jar ' B ' is at pressure ' 2 P ', volume ' V/4 ' and temperature ' T/4 '. Then the ratio of the number of molecules in jar A and jar B will be (a) 1: 1 (b) 1: 2 (c) 2: 1 (d) 4: 1

Answer: (b). N ∝ PV/T. NA ∝ PV/T, NB ∝ (2P/4)/(T/4) = 2PV/T. NA: NB = 1: 2. So the answer is (b) 1: 2.

The pressure ' P ', volume ' V ' and temperature ' T ' of a gas in a… | MHT CET 2025 (23 Apr, Shift 1)

Q26MHT CET 2025 · 23 APR · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

The pressure ' P ', volume ' V ' and temperature ' T ' of a gas in a jar ' $A$ ' and the gas in other jar ' $B$ ' is at pressure ' 2 P ', volume ' $\frac{V}{4}$ ' and temperature ' $\frac{T}{4}$ '. Then the ratio of the number of molecules in jar A and jar B will be

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Answer: (b)

$N \propto \frac{PV}{T}$ .
$N_A \propto \frac{PV}{T}$ , $N_B \propto \frac{2P\cdot\frac{V}{4}}{\frac{T}{4}} = \frac{2PV}{T}$ .
$N_A : N_B = 1 : 2$ .
So the answer is (b) $1 : 2$ .

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Gas Laws & Ideal Gas Equation question from MHT CET 2025 (23 Apr, Shift 1)

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