The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux φ linked with the primary coil is given by φ = φ 0 + 4t, where φ is webers, t is time in seconds and φ 0 is a constant, the output voltage across the secondary coil is (a) 120 volt (b) 220 volts (c) 30 volts (d) 90 volts.

Answer: (a). Primary emf Vp = (dφ)/(dt) = d/dt(φ₀ + 4t) = 4 V. Vs = Vp(Ns)/(Np) = 4 × (1500)/(50) = 120 V So the answer is (a) 120 volt.

The primary and secondary coils of a transformer have 50 and 1500… | NEET 2007 (AIPMT)

Q54NEET 2007 · AIPMTMedium

AC Generator & Transformer

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux $\phi$ linked with the primary coil is given by $\phi = \phi$ 0 + 4t, where $\phi$ is webers, t is time in seconds and $\phi$ 0 is a constant, the output voltage across the secondary coil is

Show answer and solution

Answer: (a)

Primary emf $V_p = \dfrac{d\phi}{dt} = \dfrac{d}{dt}(\phi_0 + 4t) = 4\text{ V}$ .
$V_s = V_p\dfrac{N_s}{N_p} = 4 \times \dfrac{1500}{50} = 120\text{ V}$
So the answer is (a) 120 volt.

Report a mistake

AC Generator & Transformer question from NEET 2007 (AIPMT)

More questions on AC Generator & Transformer