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JEE Main 2026 (21 Jan, Shift 2) · Molecular Speeds & Maxwell Distribution

Molecular Speeds & Maxwell Distribution question from JEE Main 2026 (21 Jan, Shift 2)

Q8JEE Main 2026 · 21 JAN · SHIFT 2Medium

Molecular Speeds & Maxwell Distribution

The r.m.s. speed of oxygen molecules at 47 °C is equal to that of the hydrogen molecules kept at _________ °C. (Mass of oxygen molecule/mass of hydrogen molecule = 32/2)

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Answer: (b)

  1. Equal vrmsv_{rms} means equal TM\frac{T}{M}.
  2. TO=47+273=320 KT_O = 47 + 273 = 320\text{ K}; TH=320×232=20 KT_H = 320 \times \frac{2}{32} = 20\text{ K}
  3. 20−273=−253∘C20 - 273 = -253^\circ\text{C}
  4. So the answer is (b) −253-253.
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