The r.m.s. value of potential difference V shown in the figure is (a) (V₀)/(√(3)) (b) V0 (c) (V₀)/(√(2)) (d) V₀/2

Answer: (c). Vrms² = average of V² over one period. V = V₀ for 0 to T/2 and V = 0 for T/2 to T. Vrms² = (V₀² · T/2 + 0)/(T) = (V₀²)/(2) Vrms = (V₀)/(√(2)), so the answer is (c).

The r.m.s. value of potential difference V shown in the figure is | NEET 2011 (AIPMT, Mains)

Q42NEET 2011 · AIPMT · MAINSEasy

AC Basics: Peak, RMS & Average Values

The r.m.s. value of potential difference V shown in the figure is

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Answer: (c)

$V_{rms}^2 =$ average of $V^2$ over one period.
$V = V_0$ for $0$ to $\frac{T}{2}$ and $V = 0$ for $\frac{T}{2}$ to $T$ .
$V_{rms}^2 = \frac{V_0^2 \cdot \frac{T}{2} + 0}{T} = \frac{V_0^2}{2}$
$V_{rms} = \frac{V_0}{\sqrt{2}}$ , so the answer is (c).

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AC Basics: Peak, RMS & Average Values question from NEET 2011 (AIPMT, Mains)

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