The radius of fifth orbit of the Li⁺⁺ is __________ × 10⁻¹² m. Take: radius of hydrogen atom = 0.51 A Numerical answer type. Work it out, then open the answer.

Answer: 425. rn = r₀n²/Z, with r₀ = 0.51 A, Z = 3 for Li⁺⁺, n = 5. r₅ = 0.51 × 25/3 = 4.25 A 4.25 A = 425 × 10⁻¹² m So the answer is 425 ( × 10⁻¹² m).

The radius of fifth orbit of the Li⁺⁺ is __________ × 10⁻¹² m. Take… | JEE Main 2023 (6 Apr, Shift 1)

Q62JEE Main 2023 · 6 APR · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

The radius of fifth orbit of the $\text{Li}^{++}$ is __________ $\times 10^{-12}\text{ m}$ .

Take: radius of hydrogen atom $= 0.51\ \mathring{A}$

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 425

$r_n = r_0\frac{n^2}{Z}$ , with $r_0 = 0.51\ \mathring{A}$ , $Z = 3$ for $\text{Li}^{++}$ , $n = 5$ .
$r_5 = 0.51 \times \frac{25}{3} = 4.25\ \mathring{A}$
$4.25\ \mathring{A} = 425 \times 10^{-12}\text{ m}$
So the answer is $425$ ( $\times 10^{-12}$ m).

Report a mistake

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2023 (6 Apr, Shift 1)

More questions on Bohr Model: Orbits, Speed & Angular Momentum