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MHT CET 2026 (18 Apr, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (18 Apr, Shift 1)

Q20MHT CET 2026 · 18 APR · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

The radius of gyration K of a hollow sphere of mass M and radius R about an axis XY is equal to R as shown in figure. The distance of that axis from the center of the sphere is h. The value of h is

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Answer: (a)

Parallel axis: $I_{XY} = \frac{2}{3}MR^2 + Mh^2$ .
$K = R \Rightarrow I_{XY} = MR^2$ , so $h^2 = R^2 - \frac{2}{3}R^2 = \frac{R^2}{3}$ .
So the answer is (a) $\frac{R}{\sqrt{3}}$ .

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