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JEE Main 2022 (26 Jul, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2022 (26 Jul, Shift 2)

Q115JEE Main 2022 · 26 JUL · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be ___________ m\text{m}.

Given, the length of the rod is 103 m10\sqrt{3}\text{ m}.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. Thin rod about centre: I=ML212⇒K=L12=L23I = \frac{ML^2}{12} \Rightarrow K = \frac{L}{\sqrt{12}} = \frac{L}{2\sqrt{3}}.
  2. K=10323=5 mK = \frac{10\sqrt{3}}{2\sqrt{3}} = 5\text{ m}
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