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MHT CET 2026 (19 Apr, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2026 (19 Apr, Shift 1)

Q19MHT CET 2026 · 19 APR · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

The radius of gyration of a solid sphere of radius 'R' and mass 'M' about its diameter is $K_d$ and that about a tangent of a solid sphere is $K_t$ . The ratio of $K_d$ to $K_t$ is

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Answer: (c)

Diameter: $K_d^2 = \frac{2}{5}R^2$ . Tangent: $K_t^2 = \frac{2}{5}R^2 + R^2 = \frac{7}{5}R^2$ .
$\frac{K_d}{K_t} = \sqrt{\frac{2}{7}}$
So the answer is (c) $\left(\frac{2}{7}\right)^{1/2}$ .

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