The radius of the earth and the radius of orbit around the sun are 6371 km and 149 × 10⁶ km respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by (a) 10³ (b) 10² (c) 10⁴ (d) 10⁵

Answer: (c). Ratio of diameters = ratio of radii: 149×10⁶6371 ≈ 2.3×10⁴. 2.3 < 3.16, so the order of magnitude is 10⁴. So the answer is (c) 10⁴.

The radius of the earth and the radius of orbit around the sun are… | MHT CET 2019 (2 May, Shift 1)

Q21MHT CET 2019 · 2 MAY · SHIFT 1Easy

Kepler's Laws & Planetary Motion

The radius of the earth and the radius of orbit around the sun are 6371 km and $149 \times 10^{6}\text{ km}$ respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by

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Answer: (c)

Ratio of diameters = ratio of radii: $\dfrac{149\times10^{6}}{6371} \approx 2.3\times10^{4}$ .
$2.3 < 3.16$ , so the order of magnitude is $10^{4}$ .
So the answer is (c) $10^{4}$ .

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