The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of 5 m/s. The work done by the unknown resistive force is ______ J. (take g = 10 m/s²) (a) -8.75 (b) -8.35 (c) -9.55 (d) -9.98

Answer: (d). Wg = mgh = 10⁻³ × 10 × 1000 = 10 J Final KE = 1/2(10⁻³)(5)² = 0.0125 J Wr = Δ K - Wg = 0.0125 - 10 = -9.9875 ≈ -9.98 J So the answer is (d).

The rain drop of mass 1 g, starts with zero velocity from a height of… | JEE Main 2026 (6 Apr, Shift 1)

Q1JEE Main 2026 · 6 APR · SHIFT 1Easy

Work-Energy Theorem

The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of $5\text{ m/s}$ . The work done by the unknown resistive force is ______ J.

(take $g = 10\text{ m/s}^2$ )

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Answer: (d)

$W_g = mgh = 10^{-3} \times 10 \times 1000 = 10\text{ J}$
Final KE $= \frac{1}{2}(10^{-3})(5)^2 = 0.0125\text{ J}$
$W_r = \Delta K - W_g = 0.0125 - 10 = -9.9875 \approx -9.98\text{ J}$
So the answer is (d).

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