The rate of flow of heat through a copper rod with temperature difference 28 is 1400 cal s⁻¹. The thermal resistance of copper rod will be (a) 0.05 ( s)/(cal) (b) 0.02 ( s)/(cal) (c) 5 ( s)/(cal) (d) 2 ( s)/(cal)

Answer: (b). Thermal resistance R = (Δ T)/(H) R = (28)/(1400) = 0.02 s/cal So the answer is (b).

The rate of flow of heat through a copper rod with temperature… | MHT CET 2021 (22 Sep, Shift 2)

Q33MHT CET 2021 · 22 SEP · SHIFT 2Easy

Heat Conduction

The rate of flow of heat through a copper rod with temperature difference $28^\circ\text{C}$ is $1400\text{ cal s}^{-1}$ . The thermal resistance of copper rod will be

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Answer: (b)

Thermal resistance $R = \frac{\Delta T}{H}$
$R = \frac{28}{1400} = 0.02\ ^\circ\text{C s/cal}$
So the answer is (b).

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