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MHT CET 2025 (19 Apr, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2025 (19 Apr, Shift 1)

Q22MHT CET 2025 · 19 APR · SHIFT 1Easy

Current Loop as a Magnetic Dipole

The ratio of angular momentum LL of an electron to the magnetic dipole moment m⃗\vec{m}orb is ( ' mm ' is mass of electron, ' ee ' is charge on electron)

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Answer: (b)

  1. Orbital moment: μ=e2mL\mu = \frac{e}{2m}L.
  2. Lμ=2me\frac{L}{\mu} = \frac{2m}{e}, so the answer is (b).
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