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MHT CET 2025 (20 Apr, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2025 (20 Apr, Shift 2)

Q39MHT CET 2025 · 20 APR · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

The ratio of angular momentum of an electron in $n$ th orbit of hydrogen atom to the velocity of electron in $n$ th orbit is proportional to

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Answer: (a)

$L = mvr \Rightarrow \frac{L}{v} = mr$
$r \propto n^2$ , so $\frac{L}{v} \propto n^2$
So the answer is (a) $n^2$ .

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