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MHT CET 2026 (13 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (13 Apr, Shift 1)

Q27MHT CET 2026 · 13 APR · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

The ratio of centripetal acceleration for an electron revolving in 3rd and 5th Bohr orbit of hydrogen atom is

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Answer: (c)

$a = \frac{v^2}{r}$ with $v \propto \frac{1}{n}$ , $r \propto n^2 \Rightarrow a \propto \frac{1}{n^4}$
$\frac{a_3}{a_5} = \frac{5^4}{3^4} = \frac{625}{81}$
So the answer is (c) $625 : 81$ .

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