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JEE Main 2023 (29 Jan, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2023 (29 Jan, Shift 2)

Q69JEE Main 2023 · 29 JAN · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

The ratio of de-Broglie wavelength of an α\alpha particle and a proton accelerated from rest by the same potential is 1m\frac{1}{\sqrt{m}}, the value of m is -

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Answer: (c)

  1. λ=h2mqV⇒λ∝1mq\lambda = \dfrac{h}{\sqrt{2mqV}} \Rightarrow \lambda \propto \dfrac{1}{\sqrt{mq}} for the same VV.
  2. λαλp=mpe4mp⋅2e=18\dfrac{\lambda_\alpha}{\lambda_p} = \sqrt{\dfrac{m_p e}{4m_p \cdot 2e}} = \dfrac{1}{\sqrt{8}}
  3. So m=8m = 8, answer (c).
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