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MHT CET 2021 (21 Sep, Shift 2) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2021 (21 Sep, Shift 2)

Q20MHT CET 2021 · 21 SEP · SHIFT 2Medium

Satellite Energy & Weightlessness

The ratio of energy required to raise a satellite of mass 'mm' to height 'hh' above the earth's surface to that required to put it into the orbit at same height is [ R=R = radius of earth]

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Answer: (d)

  1. Energy to raise: GMmhR(R+h)\frac{GMmh}{R(R+h)}.
  2. Energy to put into orbit (orbital KE): GMm2(R+h)\frac{GMm}{2(R+h)}.
  3. Ratio =2hR= \frac{2h}{R}.
  4. So the answer is (d) 2hR\frac{2h}{R}.
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