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MHT CET 2023 (11 May, Shift 2) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2023 (11 May, Shift 2)

Q17MHT CET 2023 · 11 MAY · SHIFT 2Medium

Satellite Energy & Weightlessness

The ratio of energy required to raise a satellite to a height ' $h$ ' above the earth's surface to that required to put it into the orbit at the same height is ( $R =$ radius of earth)

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Answer: (a)

Energy to raise: $\frac{GMmh}{R(R+h)}$ .
Energy to put into orbit (orbital KE): $\frac{GMm}{2(R+h)}$ .
Ratio $= \frac{2h}{R}$ .
So the answer is (a) $\frac{2h}{R}$ .

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