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NEET 2016 (Phase 1) · Escape Velocity

Escape Velocity question from NEET 2016 (Phase 1)

Q67NEET 2016 · PHASE 1Easy

Escape Velocity

The ratio of escape velocity at earth (ve) to the escape velocity at a planet (vp) whose radius and mean density are twice as that of earth is

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Answer: (d)

  1. ve∝Rρv_e \propto R\sqrt{\rho}
  2. vpve=22\frac{v_p}{v_e} = 2\sqrt{2}
  3. So the answer is (d) ve:vp=1:22v_e : v_p = 1 : 2\sqrt{2}.
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